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Proof step 22 from proof bytes2int-len-one-01 (previous step)

b2i(by) < 128, 0 ≤ b2i(by) ⊦ by0 = i2b(0), true ∈ bytes2bits(bytes), true ∈ byte2bits(by0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ byte2bits(by) = fillsgn(8, int2bits(b2i(by)))
Proof step 24:
b2i(by) < 128, 0 ≤ b2i(by) ⊦ by0 = i2b(0), true ∈ bytes2bits(bytes), true ∈ fillsgn(8, int2bits(b2i(by0)))

Rule argument

name: byte2bits rotate: F subst: [by] → [by0]

Additional information

Used terms: by0