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Proof step 7 from proof bytes2int-len-one-01 (previous step)

bytes0 ≠ [], bytes2int(bytes0) * 256 + band(b2i(by), 255) < 128, 0 ≤ bytes2int(bytes0) * 256 + band(b2i(by), 255) ⊦ bytes0 = [], bytes0.first = i2b(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
bytes2int(bytes0) * 256 + band(b2i(by), 255) < 128, 0 ≤ bytes2int(bytes0) * 256 + band(b2i(by), 255) ⊦ bytes0.first = i2b(0), bytes0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)