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Proof step 5 from proof bytes2int-len-one-02 (previous step)

bytes0 = by + bytes, 0 ≤ bytes2int(i2b(0) ' + bytes0), b2i(by) < 0, bytes2int(i2b(0) ' + bytes0) < 128 ⊦ bytes0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
b2i(by) < 0, 0 ≤ bytes2int(i2b(0) ' + by ' + bytes), bytes2int(i2b(0) ' + by ' + bytes) < 128 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes ≠ [];% ⊦ by + bytes = by ' + bytes;