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Proof step 11 from proof bytes2int-mklist-mones-01 (previous step)

bytes = by + bytes1, bytes = by ', b2i(by) < 0, ∀ n, bytes0. # bytes0 < 1 → b2i(bytes0.first) < 0 → bytes2int(mklist(i2b(~1), n) + bytes0) = bytes2int(bytes0) ∨ bytes0 = [] ⊦ bytes = [], bytes2int(mklist(i2b(~1), n) + bytes) = bytes2int(bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
b2i(by) < 0, ∀ n, bytes0. # bytes0 < 1 → b2i(bytes0.first) < 0 → bytes2int(mklist(i2b(~1), n) + bytes0) = bytes2int(bytes0) ∨ bytes0 = [] ⊦ bytes2int(mklist(i2b(~1), n) + by ') = b2i(by)

Rule argument

Additional information

Used simplifier rules: bytes2int-one: ⊦ bytes2int(by ') = b2i(by);% ⊦ bytes + [] = bytes;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ by ' + bytes ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' = by0 ' + bytes ↔ by = by0 ∧ bytes = [];% ⊦ by + bytes = by ' + bytes;