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Proof step 9 from proof bytes2int-mklist-mones-01 (previous step)

bytes = bytes.first + [], b2i(bytes.first) < 0, ∀ n, bytes0. # bytes0 < 1 → b2i(bytes0.first) < 0 → bytes2int(mklist(i2b(~1), n) + bytes0) = bytes2int(bytes0) ∨ bytes0 = [] ⊦ bytes = [], bytes2int(mklist(i2b(~1), n) + bytes) = bytes2int(bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
bytes = bytes.first ', b2i(bytes.first) < 0, ∀ n, bytes0. # bytes0 < 1 → b2i(bytes0.first) < 0 → bytes2int(mklist(i2b(~1), n) + bytes0) = bytes2int(bytes0) ∨ bytes0 = [] ⊦ bytes = [], bytes2int(mklist(i2b(~1), n) + bytes) = bytes2int(bytes)

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + [] = bytes;% ⊦ by + bytes = by ' + bytes;