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Proof step 2 from proof bytes2int-mklist-zeros-01 (previous step)

0 ≤ b2i(bytes.first) ⊦ bytes2int(mklist(i2b(0), n) + bytes) = bytes2int(bytes), bytes = []

User applied rule induction

And obtained the following new goals

Proof step 3:
0 ≤ b2i(bytes.first), ∀ n, bytes0. # bytes0 < # bytes → 0 ≤ b2i(bytes0.first) → bytes2int(mklist(i2b(0), n) + bytes0) = bytes2int(bytes0) ∨ bytes0 = [] ⊦ bytes2int(mklist(i2b(0), n) + bytes) = bytes2int(bytes) ∨ bytes = []

Rule argument

indvar: # bytes wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bytes