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Proof step 14 from proof bytes2int-mone (previous step)

b2i(by) < 0 ⊦ bits2int(true ' + byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ bits2int(bits) = bits2int(sgn(bits))
Proof step 16:
b2i(by) < 0 ⊦ bits2int(sgn(true ' + byte2bits(by) + bytes2bits(bytes))) = bits2int(byte2bits(by) + bytes2bits(bytes))

Rule argument

seq: ⊦ bits2int(bits) = bits2int(sgn(bits)) subst: [bits] → [true ' + byte2bits(by) + bytes2bits(bytes)] rotate: F spec: int2bits inst: name: bits2int-sgn-intro

Additional information

Used terms: true ' + byte2bits(by) + bytes2bits(bytes)