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Proof step 2 from proof bytes2int-mone (previous step)

b2i(by) < 0 ⊦ bytes2int(i2b(~1) ' + by ' + bytes) = bytes2int(by ' + bytes)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 4:
b2i(by) < 0 ⊦ bits2int(bytes2bits(i2b(~1) ' + by ' + bytes)) = bytes2int(by ' + bytes)

Rule argument

name: bytes2int rotate: F subst: [bytes] → [i2b(~1) ' + by ' + bytes]

Additional information

Used terms: i2b(~1) ' + by ' + bytes