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Proof step 5 from proof bytes2int-mone (previous step)

b2i(by) < 0 ⊦ bits2int(byte2bits(i2b(~1)) + byte2bits(by) + bytes2bits(bytes)) = bytes2int(by ' + bytes)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 7:
b2i(by) < 0 ⊦ bits2int(byte2bits(i2b(~1)) + byte2bits(by) + bytes2bits(bytes)) = bits2int(bytes2bits(by ' + bytes))

Rule argument

name: bytes2int rotate: F subst: [bytes] → [by ' + bytes]

Additional information

Used terms: by ' + bytes