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Proof step 8 from proof bytes2int-mone (previous step)

b2i(by) < 0 ⊦ bits2int(byte2bits(i2b(~1)) + byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ byte2bits(i2b(~1)) = mklist(true, 8)
Proof step 10:
b2i(by) < 0 ⊦ bits2int(mklist(true, 8) + byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Rule argument

name: byte2bits-mone rotate: F subst:

Additional information

Used terms: