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Proof step 17 from proof bytes2int-neg (previous step)

bytes2int(by ' + bytes) < 0, 0 ≤ band(255, b2i(by0)) + 256 * bytes2int(by ' + bytes), b2i(by) < 0, ∀ bytes0. # bytes0 < #(by + (bytes + by0 ')) → true → bytes0 ≠ [] → (bytes2int(bytes0) < 0 ↔ b2i(bytes0.first) < 0) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ i + j = j + i
Proof step 19:
bytes2int(by ' + bytes) < 0, 0 ≤ 256 * bytes2int(by ' + bytes) + band(255, b2i(by0)), b2i(by) < 0, ∀ bytes0. # bytes0 < #(by + (bytes + by0 ')) → true → bytes0 ≠ [] → (bytes2int(bytes0) < 0 ↔ b2i(bytes0.first) < 0) ⊦

Rule argument

seq: ⊦ i + j = j + i subst: [j, i] → [256 * bytes2int(by ' + bytes), band(255, b2i(by0))] rotate: F spec: int-basic2 inst: name: add-c

Additional information

Used terms: 256 * bytes2int(by ' + bytes), band(255, b2i(by0))