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Proof step 2 from proof bytes2int-pos (previous step)

⊦ 0 ≤ bytes2int(bytes) ↔ bytes = [] ∨ ¬ b2i(bytes.first) < 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 4:
⊦ 0 ≤ bits2int(bytes2bits(bytes)) ↔ bytes = [] ∨ ¬ b2i(bytes.first) < 0

Rule argument

name: bytes2int rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes