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Proof step 1 from proof bytes2int-rec-01 (conclusion)

⊦ 1 < # bytes → bytes2int(bytes) = bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bytes2int(bytes) = bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255), # bytes = 1, bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);