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Proof step 3 from proof bytes2int-rec-01 (previous step)

bytes = bytes0 + by ' ⊦ bytes2int(bytes) = bytes2int(bytes0) * 256 + band(b2i(by), 255), # bytes = 1, bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ bytes2int(bytes0 + by ') = bytes2int(bytes0) * 256 + band(b2i(by), 255), bytes0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ bytes + by ' ≠ [];% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;