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Proof step 3 from proof bytes2int-rec-first-zero (previous step)

true, ∀ by, bytes0. # bytes0 < # bytes → true → bytes0 = [] ∨ bytes2int(i2b(0) ' + by ' + bytes0) = band(b2i(by), 255) * 256 ^ n→i(# bytes0) + bytes2int(i2b(0) ' + bytes0) ⊦ bytes = [] ∨ bytes2int(i2b(0) ' + by ' + bytes) = band(b2i(by), 255) * 256 ^ n→i(# bytes) + bytes2int(i2b(0) ' + bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ by, bytes0. # bytes0 < # bytes → true → bytes0 = [] ∨ bytes2int(i2b(0) ' + by ' + bytes0) = band(b2i(by), 255) * 256 ^ n→i(# bytes0) + bytes2int(i2b(0) ' + bytes0) ⊦ bytes2int(i2b(0) ' + by ' + bytes) = band(b2i(by), 255) * 256 ^ n→i(# bytes) + bytes2int(i2b(0) ' + bytes), bytes = []

Proof step 3 from proof bytes2int-rec-first-zero (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information