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Proof step 18 from proof bytes2int-rec (previous step)

bytes2bits(bytes) ≠ [], bytes2bits(bytes).first ⊦ bitsinvert(bytes2bits(bytes)) + bitsinvert(byte2bits(by)) = [], bytes2bits(bytes) + byte2bits(by) = [], bytes = [], ~1 = bits2uint(bitsinvert(bytes2bits(bytes)) + bitsinvert(byte2bits(by))) + bits2int(bytes2bits(bytes)) * 256 + band(b2i(by), 255)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
bytes2bits(bytes).first ⊦ bitsinvert(bytes2bits(bytes)) + bitsinvert(byte2bits(by)) = [], bytes2bits(bytes) + byte2bits(by) = [], bytes = [], ~1 = bits2uint(bitsinvert(bytes2bits(bytes)) + bitsinvert(byte2bits(by))) + bits2int(bytes2bits(bytes)) * 256 + band(b2i(by), 255)

Rule argument

Additional information

Used simplifier rules: bytes2bits-empty-01: ⊦ bytes2bits(bytes) = [] ↔ bytes = [];