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Proof step 33 from proof bytes2int-rec (previous step)

¬ (bytes2bits(bytes) + byte2bits(by)).first ∧ bytes2bits(bytes) + byte2bits(by) ≠ [] ⊦ bytes = [], bits2uint(bytes2bits(bytes) + byte2bits(by)) = bits2int(bytes2bits(bytes)) * 256 + band(b2i(by), 255)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
⊦ bytes2bits(bytes) + byte2bits(by) = [], bits2uint(bytes2bits(bytes) + byte2bits(by)) = bits2int(bytes2bits(bytes)) * 256 + band(b2i(by), 255), bytes = [], (bytes2bits(bytes) + byte2bits(by)).first

Proof step 33 from proof bytes2int-rec (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information