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Proof step 4 from proof bytes2int-rec (previous step)

⊦ bytes = [], bits2int(bytes2bits(bytes + by ')) = bytes2int(bytes) * 256 + band(b2i(by), 255)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ bytes = [], bits2int(bytes2bits(bytes) + byte2bits(by)) = bytes2int(bytes) * 256 + band(b2i(by), 255)

Rule argument

Additional information

Used simplifier rules: bytes2bits-append: ⊦ bytes2bits(bytes + bytes0) = bytes2bits(bytes) + bytes2bits(bytes0);%bytes2bits-one: ⊦ bytes2bits(by ') = byte2bits(by);% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;