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Proof step 10 from proof bytes2int-size-03 (previous step)

0 < b2i(by), band(255, b2i(by0)) + 256 * bytes2int(by ' + bytes1) < 2 ^ (8 * (n→i(# bytes1) + 1)), ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(by ' + bytes0) < 2 ^ (n→i(# bytes0) * 8) ∧ 0 < b2i(by) → false ⊦ bytes2int(by ' + bytes1) < 2 ^ (n→i(# bytes1) * 8) ∧ 0 < b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 < b2i(by), band(255, b2i(by0)) + 256 * bytes2int(by ' + bytes1) < 2 ^ (8 * (n→i(# bytes1) + 1)), 2 ^ (n→i(# bytes1) * 8) ≤ bytes2int(by ' + bytes1), ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(by ' + bytes0) < 2 ^ (n→i(# bytes0) * 8) ∧ 0 < b2i(by) → false ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;