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Proof step 1 from proof bytes2int-size-04 (conclusion)

⊦ b2i(by) < 0 → ~(2 ^ ((n→i(# bytes) + 1) * 8 - 1)) ≤ bytes2int(by ' + bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
b2i(by) < 0, 2 ^ ((n→i(# bytes) + 1) * 8 - 1) + bytes2int(by ' + bytes) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;