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Proof step 1 from proof bytes2int-size-05 (conclusion)

⊦ 0 ≤ b2i(by) → ~(2 ^ ((n→i(# bytes) + 1) * 8)) ≤ bytes2int(i2b(~1) ' + by ' + bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
2 ^ ((n→i(# bytes) + 1) * 8) + bytes2int(i2b(~1) ' + by ' + bytes) < 0, 0 ≤ b2i(by) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;