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Proof step 10 from proof bytes2int-size-05 (previous step)

bytes = bytes1 + by0 ', 2 ^ ((n→i(# bytes) + 1) * 8) + 256 * bytes2int(i2b(~1) ' + by ' + bytes1) + band(255, b2i(by0)) < 0, 0 ≤ b2i(by), ∀ by, bytes0. # bytes0 < # bytes → 2 ^ ((n→i(# bytes0) + 1) * 8) + bytes2int(i2b(~1) ' + by ' + bytes0) < 0 ∧ 0 ≤ b2i(by) → false ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
band(255, b2i(by0)) + 256 * bytes2int(i2b(~1) ' + by ' + bytes1) + 2 ^ (8 * (2 + n→i(# bytes1))) < 0, 0 ≤ b2i(by), ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → 2 ^ ((n→i(# bytes0) + 1) * 8) + bytes2int(i2b(~1) ' + by ' + bytes0) < 0 ∧ 0 ≤ b2i(by) → false ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ n→i(m + n) = n→i(m) + n→i(n);% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + by ' ≠ [];