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Proof step 1 from proof bytes2int-size-06 (conclusion)

⊦ b2i(by) < 0 ∧ b2i(by) ≠ ~1 → bytes2int(by ' + bytes) < ~(2 ^ (8 * n→i(# bytes)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ bytes2int(by ' + bytes) + 2 ^ (8 * n→i(# bytes)), b2i(by) < 0 ⊦ b2i(by) = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < ~ j ↔ i + j < 0;