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Proof step 3 from proof bytes2int-size-06 (previous step)

0 ≤ bytes2int(by ' + bytes) + 2 ^ (8 * n→i(# bytes)) ∧ b2i(by) < 0, ∀ by, bytes0. # bytes0 < # bytes → 0 ≤ bytes2int(by ' + bytes0) + 2 ^ (8 * n→i(# bytes0)) ∧ b2i(by) < 0 → b2i(by) = ~1 ⊦ b2i(by) = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
b2i(by) < 0, 0 ≤ bytes2int(by ' + bytes) + 2 ^ (8 * n→i(# bytes)), ∀ by, bytes0. # bytes0 < # bytes → 0 ≤ bytes2int(by ' + bytes0) + 2 ^ (8 * n→i(# bytes0)) ∧ b2i(by) < 0 → b2i(by) = ~1 ⊦ b2i(by) = ~1

Proof step 3 from proof bytes2int-size-06 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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