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Proof step 8 from proof bytes2int-size-07 (previous step)

0 ≤ b2i(by), 0 ≤ 2 ^ (8 * (n→i(# bytes) + 1) - 1) + band(255, b2i((by ' + bytes).last)) + 256 * bytes2int(i2b(~1) ' + (by ' + bytes).butlast), ∀ by, bytes0. # bytes0 < # bytes → 0 ≤ b2i(by) ∧ 0 ≤ bytes2int(i2b(~1) ' + by ' + bytes0) + 2 ^ (8 * (n→i(# bytes0) + 1) - 1) → false ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 ≤ b2i(by), 0 ≤ 256 * bytes2int(i2b(~1) ' + by ' + bytes.butlast) + band(255, b2i(bytes.last)) + 2 ^ (8 * (n→i(# bytes) + 1) - 1), ∀ by, bytes0. # bytes0 < # bytes → 0 ≤ b2i(by) ∧ 0 ≤ bytes2int(i2b(~1) ' + by ' + bytes0) + 2 ^ (8 * (n→i(# bytes0) + 1) - 1) → false ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ bytes ≠ [] → (by ' + bytes).last = bytes.last;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes ≠ [] → (bytes0 + bytes).butlast = bytes0 + bytes.butlast;