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Proof step 3 from proof bytes2int-size-val-05 (previous step)

⊦ ¬ b2i(i2b(0)) < 0 ∧ 2 ^ ((n→i(# mklist(i2b(0), n)) + 1) * 8) + bytes2int(i2b(~1) ' + i2b(0) ' + mklist(i2b(0), n)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ bytes2int(i2b(~1) ' + i2b(0) ' + mklist(i2b(0), n)) + 2 ^ (8 * (1 + n→i(n))) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ # mklist(by, n) = n;% ⊦ b2i(i2b(0)) = 0;