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Proof step 1 from proof bytes2int-size-val-06 (conclusion)

⊦ ∃ by, bytes. b2i(by) < 0 ∧ b2i(by) ≠ ~1 ∧ bytes2int(by ' + bytes) = ~(2 ^ (8 * n→i(# bytes)) + 1)

User applied rule exists right

And obtained the following new goals

Proof step 2:
⊦ b2i(i2b(~2)) < 0 ∧ b2i(i2b(~2)) ≠ ~1 ∧ bytes2int(i2b(~2) ' + mklist(i2b(~1), n)) = ~(2 ^ (8 * n→i(# mklist(i2b(~1), n))) + 1)

Rule argument

pos: right 1 terms: i2b(~2), mklist(i2b(~1), n) abort: F discard: T computed: F

Additional information

Used terms: i2b(~2), mklist(i2b(~1), n)