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Proof step 3 from proof bytes2int-size-val (previous step)

⊦ ¬ 0 ≤ b2i(i2b(~1)) ∧ 2 ^ ((n→i(# mklist(i2b(~1), n)) + 1) * 8) = bytes2int(i2b(0) ' + i2b(~1) ' + mklist(i2b(~1), n)) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ 2 ^ (8 * (1 + n→i(n))) = bytes2int(i2b(0) ' + i2b(~1) ' + mklist(i2b(~1), n)) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ # mklist(by, n) = n;%~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i;