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Proof step 5 from proof bytes2int-size-val (previous step)

⊦ i2b(0) ' + i2b(~1) ' + mklist(i2b(~1), n) = i2b(0) ' + mklist(i2b(~1), n + 1), 2 ^ (8 * (1 + n→i(n))) = bytes2int(i2b(0) ' + i2b(~1) ' + mklist(i2b(~1), n)) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ 2 ^ (8 * (1 + n→i(n))) = bytes2int(i2b(0) ' + i2b(~1) ' + mklist(i2b(~1), n)) + 1, i2b(~1) ' + mklist(i2b(~1), n) = mklist(i2b(~1), n + 1)

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + bytes0 = bytes + bytes1 ↔ bytes0 = bytes1;