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Proof step 1 from proof bytes2int-size (conclusion)

⊦ b2i(by) < 0 → bytes2int(i2b(0) ' + by ' + bytes) < 2 ^ ((n→i(# bytes) + 1) * 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
2 ^ ((n→i(# bytes) + 1) * 8) ≤ bytes2int(i2b(0) ' + by ' + bytes), b2i(by) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;