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Proof step 12 from proof bytes2int-size (previous step)

b2i(by) < 0, 2 ^ (8 * (2 + n→i(# bytes1))) ≤ 256 * bytes2int(i2b(0) ' + by ' + bytes1) + band(255, b2i(by0)), ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → 2 ^ ((n→i(# bytes0) + 1) * 8) ≤ bytes2int(i2b(0) ' + by ' + bytes0) ∧ b2i(by) < 0 → false ⊦ 2 ^ ((n→i(# bytes1) + 1) * 8) ≤ bytes2int(i2b(0) ' + by ' + bytes1) ∧ b2i(by) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
b2i(by) < 0, 2 ^ (8 * (2 + n→i(# bytes1))) ≤ 256 * bytes2int(i2b(0) ' + by ' + bytes1) + band(255, b2i(by0)), bytes2int(i2b(0) ' + by ' + bytes1) < 2 ^ ((n→i(# bytes1) + 1) * 8), ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → 2 ^ ((n→i(# bytes0) + 1) * 8) ≤ bytes2int(i2b(0) ' + by ' + bytes0) ∧ b2i(by) < 0 → false ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;