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Proof step 4 from proof bytes2int-zero-02 (previous step)

⊦ bits2int(byte2bits(i2b(0)) + byte2bits(i2b(0)) + bytes2bits(bytes)) = bytes2int(i2b(0) ' + bytes)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 6:
⊦ bits2int(byte2bits(i2b(0)) + byte2bits(i2b(0)) + bytes2bits(bytes)) = bits2int(bytes2bits(i2b(0) ' + bytes))

Rule argument

name: bytes2int rotate: F subst: [bytes] → [i2b(0) ' + bytes]

Additional information

Used terms: i2b(0) ' + bytes