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Proof step 17 from proof bytes2int-zero-03 (previous step)

bytes2int(bytes1) * 256 + ub2i(by0) = 0, ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(bytes0) = 0 ∧ by ∈ bytes0 → by = i2b(0) ⊦ ub2i(by0) = 0, by = i2b(0), bytes1 = [], ¬ by ∈ bytes1 ∧ by ≠ by0, ¬ bytes2int(bytes1) ≤ 0 ∧ ub2i(by0) ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
bytes2int(bytes1) * 256 + ub2i(by0) = 0, bytes2int(bytes1) ≤ 0, ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(bytes0) = 0 ∧ by ∈ bytes0 → by = i2b(0) ⊦ ub2i(by0) = 0, by = i2b(0), bytes1 = [], ¬ by ∈ bytes1 ∧ by ≠ by0

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)