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Proof step 9 from proof bytes2int-zero-03 (previous step)

bytes2int(bytes1) * 256 + band(b2i(by0), 255) = 0, ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(bytes0) = 0 ∧ by ∈ bytes0 → by = i2b(0) ⊦ by = i2b(0), bytes1 = [], ¬ by ∈ bytes1 ∧ by ≠ by0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ band(b2i(by), 255) = ub2i(by)
Proof step 11:
bytes2int(bytes1) * 256 + ub2i(by0) = 0, ∀ by, bytes0. # bytes0 < #(bytes1 + by0 ') → bytes2int(bytes0) = 0 ∧ by ∈ bytes0 → by = i2b(0) ⊦ by = i2b(0), bytes1 = [], ¬ by ∈ bytes1 ∧ by ≠ by0

Rule argument

seq: ⊦ band(b2i(by), 255) = ub2i(by) subst: [by] → [by0] rotate: F spec: byte inst: name: band-ff

Additional information

Used terms: by0