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Proof step 5 from proof bytes2int-zero-05 (previous step)

bytes2int(bytes) = 0, n < # bytes, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ bytes[n] = i2b(0), bytes = []

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: bytes[n] abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ m < # bytes → (¬ bytes[m] ∈ bytes ↔ false);% ⊦ b2i(by) = i → (i2b(i) ≠ by ↔ false); Used terms: bytes[n]