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Proof step 8 from proof bytes2int-zero-06 (previous step)

∀ by. by ∈ bytes → b2i(by) = 0, ∀ bytes0. # bytes0 < # bytes → (∀ by. by ∈ bytes0 → b2i(by) = 0) → bytes2int(bytes0) = 0 ∨ bytes0 = [] ⊦ bytes = [], bytes2int(bytes) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ 1 < # bytes → bytes2int(bytes) = bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255)
Proof step 10:
¬ 1 < # bytes, ∀ by. by ∈ bytes → b2i(by) = 0, ∀ bytes0. # bytes0 < # bytes → (∀ by. by ∈ bytes0 → b2i(by) = 0) → bytes2int(bytes0) = 0 ∨ bytes0 = [] ⊦ bytes = [], bytes2int(bytes) = 0
Proof step 14:
1 < # bytes, ∀ by. by ∈ bytes → b2i(by) = 0, ∀ bytes0. # bytes0 < # bytes → (∀ by. by ∈ bytes0 → b2i(by) = 0) → bytes2int(bytes0) = 0 ∨ bytes0 = [] ⊦ bytes = [], bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255) = 0

Rule argument

name: bytes2int-rec-01 rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes