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Proof step 2 from proof fillsgn-butlast (previous step)

⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes
Proof step 4:
¬ # bytes.butlast ≥ n ⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []
Proof step 34:
# bytes.butlast ≥ n ⊦ bytes.butlast = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [bytes.butlast, n]

Additional information

Used terms: bytes.butlast, n