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Proof step 5 from proof fillsgn-butlast (previous step)

# bytes ≤ n ⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ # bytes < n ∧ bytes2int(bytes) < 0 → fillsgn(n, bytes) = mklist(i2b(~1), n - # bytes) + bytes
Proof step 7:
¬(# bytes < n + 1 ∧ bytes2int(bytes) < 0), # bytes ≤ n ⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []
Proof step 23:
# bytes < n + 1 ∧ bytes2int(bytes) < 0, # bytes ≤ n ⊦ fillsgn(n, bytes.butlast) = (mklist(i2b(~1), n + 1 - # bytes) + bytes).butlast, # bytes = 1, bytes = []

Rule argument

name: fillsgn-neg rotate: F subst: [bytes, n] → [bytes, n + 1]

Additional information

Used terms: bytes, n + 1