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Proof step 8 from proof fillsgn-butlast (previous step)

# bytes ≤ n, 0 ≤ bytes2int(bytes) ⊦ fillsgn(n, bytes.butlast) = fillsgn(n + 1, bytes).butlast, # bytes = 1, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ # bytes < n ∧ 0 ≤ bytes2int(bytes) → fillsgn(n, bytes) = mklist(i2b(0), n - # bytes) + bytes
Proof step 10:
# bytes < n + 1 ∧ 0 ≤ bytes2int(bytes), # bytes ≤ n, 0 ≤ bytes2int(bytes) ⊦ fillsgn(n, bytes.butlast) = (mklist(i2b(0), n + 1 - # bytes) + bytes).butlast, # bytes = 1, bytes = []

Rule argument

name: fillsgn-pos rotate: F subst: [bytes, n] → [bytes, n + 1]

Additional information

Used simplifier rules: ⊦ m < n + 1 ↔ ¬ n < m;% ⊦ m ≤ n → (n < m ↔ false);% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: bytes, n + 1