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Proof step 1 from proof fillsgn-empty (conclusion)

⊦ fillsgn(n, bytes) = [] ↔ n = 0 ∧ bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes
Proof step 3:
¬ # bytes ≥ n ⊦ fillsgn(n, bytes) = [] ↔ n = 0 ∧ bytes = []

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [bytes, n]

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n;% ⊦ # [] = 0;% ⊦ m ≤ 0 ↔ m = 0; Used terms: bytes, n