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Proof step 15 from proof fillsgn-len-short (previous step)

int2bytes(s2i(sho)).first = i2b(0), 2 < # int2bytes(s2i(sho)), 0 ≤ s2i(sho) ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ 0 ≤ i ∧ int2bytes(i).first = i2b(0) → (n < # int2bytes(i) ↔ 2 ^ (n→i(n) * 8)-1 ≤ i)

Rule argument

name: int2bytes-len-ls-01 rotate: F subst: [i, n] → [s2i(sho), 2]

Additional information

Used simplifier rules: ⊦ ¬ 32768 ≤ s2i(sho);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: s2i(sho), 2