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Proof step 9 from proof fillsgn-len-short (previous step)

2 < # int2bytes(s2i(sho)), s2i(sho) < 0 ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ i < 0 ∧ int2bytes(i).first ≠ i2b(~1) → (n < # int2bytes(i) ↔ i < ~(2 ^ (8 * n→i(n))))
Proof step 11:
¬(s2i(sho) < 0 ∧ int2bytes(s2i(sho)).first ≠ i2b(~1)), 2 < # int2bytes(s2i(sho)), s2i(sho) < 0 ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

Rule argument

name: int2bytes-len-ls-neg rotate: F subst: [i, n] → [s2i(sho), 2]

Additional information

Used simplifier rules: ⊦ i ≤ ~32768 → ¬ s2i(sho) < i; Used terms: s2i(sho), 2