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Proof step 4 from proof fillsgn-length (previous step)

¬ # bytes ≥ n, # fillsgn(n, bytes) < n ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# fillsgn(n, bytes) < n, # bytes < n ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ n ≥ m ↔ m ≤ n;