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Proof step 6 from proof fillsgn-not-empty (previous step)

¬ # int2bytes(i) ≤ n, ¬ # fillsgn(n, int2bytes(i)) ≠ # [], fillsgn(n, int2bytes(i)) = [] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
fillsgn(n, int2bytes(i)) = [], n < # int2bytes(i) ⊦

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ # [] = 0;