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Proof step 10 from proof fillsgn-rec (previous step)

# bytes ≤ m, 0 ≤ bytes2int(bytes) ⊦ bytes = [], mklist(i2b(0), (m - # bytes) + 1) + bytes = (¬ 0 ≤ b2i(bytes.first) ⊃ i2b(~1);i2b(0)) ' + fillsgn(m, bytes)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
m = n + # bytes, # bytes ≤ m, 0 ≤ bytes2int(bytes) ⊦ bytes = [], mklist(i2b(0), n + 1) + bytes = (¬ 0 ≤ b2i(bytes.first) ⊃ i2b(~1);i2b(0)) ' + fillsgn(m, bytes)

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m, # bytes, n] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m, # bytes, n