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Proof step 15 from proof fillsgn-rec (previous step)

0 ≤ bytes2int(bytes) ⊦ bytes = [], i2b(0) ' + bytes = (¬ 0 ≤ b2i(bytes.first) ⊃ i2b(~1);i2b(0)) ' + fillsgn(# bytes, bytes)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes
Proof step 17:
# bytes ≥ # bytes, 0 ≤ bytes2int(bytes) ⊦ bytes = [], i2b(0) ' + bytes = (¬ 0 ≤ b2i(bytes.first) ⊃ i2b(~1);i2b(0)) ' + bytes

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [bytes, # bytes]

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ ¬ n < n; Used terms: bytes, # bytes