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Proof step 32 from proof fillsgn-rec (previous step)

bytes = by + bytes0, bytes2int(bytes) < 0 ⊦ bytes = [], mklist(i2b(~1), n + 1) + bytes = (¬ 0 ≤ b2i(by) ⊃ i2b(~1);i2b(0)) ' + fillsgn(n + # bytes, bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
bytes2int(by ' + bytes0) < 0 ⊦ mklist(i2b(~1), n + 1) + by ' + bytes0 = (¬ 0 ≤ b2i(by) ⊃ i2b(~1);i2b(0)) ' + fillsgn((1 + # bytes0) + n, by ' + bytes0)

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes ≠ [];% ⊦ by + bytes = by ' + bytes;