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Proof step 38 from proof fillsgn-rec (previous step)

#(by ' + bytes0) ≥ 1 + # bytes0, bytes2int(by ' + bytes0) < 0 ⊦ i2b(~1) ' + by ' + bytes0 = (¬ 0 ≤ b2i(by) ⊃ i2b(~1);i2b(0)) ' + by ' + bytes0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m;% ⊦ m + n ≤ m + n0 ↔ n ≤ n0;% ⊦ n ≥ m ↔ m ≤ n;% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' = by0 ' ↔ by = by0;% ⊦ bytes + bytes0 = bytes1 + bytes0 ↔ bytes = bytes1;