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Proof step 13 from proof fillsgn-short (previous step)

# int2bytes(bytes2int(bytes)) < # bytes, # int2bytes(bytes2int(bytes)) < # fillsgn(# bytes, int2bytes(bytes2int(bytes))), # int2bytes(bytes2int(bytes)) < 2, 2 < # bytes, # bytes ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))), 2 < # fillsgn(# bytes, int2bytes(bytes2int(bytes))), # int2bytes(bytes2int(bytes)) + 1 < # bytes, # int2bytes(bytes2int(bytes)) + 1 < # fillsgn(# bytes, int2bytes(bytes2int(bytes))) ⊦ int2bytes(bytes2int(bytes)) = bytes, fillsgn(# bytes, int2bytes(bytes2int(bytes))) = [], bytes = [], fillsgn(2, int2bytes(bytes2int(bytes))) = bytes ↔ int2bytes(bytes2int(bytes)) = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
fillsgn(2, int2bytes(bytes2int(bytes))) = bytes, # int2bytes(bytes2int(bytes)) < # bytes, # int2bytes(bytes2int(bytes)) < # fillsgn(# bytes, int2bytes(bytes2int(bytes))), # int2bytes(bytes2int(bytes)) < 2, 2 < # bytes, # bytes ≤ # fillsgn(# bytes, int2bytes(bytes2int(bytes))), 2 < # fillsgn(# bytes, int2bytes(bytes2int(bytes))), # int2bytes(bytes2int(bytes)) + 1 < # bytes, # int2bytes(bytes2int(bytes)) + 1 < # fillsgn(# bytes, int2bytes(bytes2int(bytes))) ⊦ int2bytes(bytes2int(bytes)) = bytes, fillsgn(# bytes, int2bytes(bytes2int(bytes))) = [], bytes = []

Proof step 13 from proof fillsgn-short (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information