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Proof step 18 from proof fillsgn-short (previous step)

2 = # bytes, 2 ≤ # fillsgn(2, int2bytes(bytes2int(bytes))) ⊦ fillsgn(2, int2bytes(bytes2int(bytes))) = bytes, bytes = [], fillsgn(2, int2bytes(bytes2int(bytes))) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ # bytes = n ∧ bytes ≠ [] → fillsgn(n, int2bytes(bytes2int(bytes))) = bytes

Rule argument

name: bytes2bytes-fillsgn rotate: F subst: [bytes, n] → [bytes, 2]

Additional information

Used terms: bytes, 2